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PREVERJANJE ZNANJA- ULOMKI

1. Izraˇcunaj:

(a) 12 9 20 −

32

5+ 16 7 12

!

−(10− 3 10

!!

[R: ] (b) 93

7 + 41

4 −125 28

!

113 16− 1

8· 5 6

!

[R: ] (c)

32 9 −15

6

!

: 1 7

18+ 213 14·42

3

!

: 11

15 [R: ]

(d) 12 3·52

5·77 9·12

7 [R: ]

2. Izraˇcunaj:

(a) 3113 : 445

145 [R: ]

(b) 11619 : 195

2101 : 123 [R: ]

(c)

1 3195

2

31019 [R: ]

(d) 556 + 1345 −6152

823 −11112 [R: ]

(e)

3 425

1 + 25 · 34 [R: ]

3. Okrajšaj ulomke:

(a) a−7

7−a [R:−1]

(b) 25a2−9b2

(5a+ 3b)2 [R:5a−3b]

(c) a3+ 1

a3+a2 [R: ]

(d) a2−4

a3−8 [R: ]

(e) a3+ 8a2+a+ 8

3a+ 24 [R: ]

(f) a4−81

a3−3a2+ 9a−27 [R: ]

(2)

4. Poenostavi:

(a) 5x2+ 30x

x2−36 : x4+ 8x3

x2+ 2x−48 = [R: ]

(b) x3+x2 −49x−49

x2 + 12x+ 35 : x5−6x4−7x3

x3+ 125 = [R: ]

(c) x4−81

x2−7x−30 : x3 −3x2+ 9x−27

x4−10x3 = [R: ]

(d) x2−9

x · x−2

2x2−6x : x2+x−6

6x3 = [R: ]

(e) x+ 5

3x2+ 12x · 15x7

x2+x−20 : x3

x2−16 = [R: ]

(f) 12x5

x2−3x−18 · x2−9

x2 : 4x2−12x

x−6 = [R: ]

5. Poenostavi (a) x+ 3

x−3− x−3 x+ 3

!

: 3x

x2−9 = [R: ]

(b) 4x+ 5

5x−2 − 4x−3 5x+ 2

!

·25x2−4

14x+ 1 = [R: ]

(c) 2x−1

5x+ 7 − 2x−3 5x−7

!

: 14−9x

25x2−49 = [R: ]

(d) 1

3− 7 x2−4x

!

· x

x−7 : x+ 3

x2−16 = [R: ]

(e) 1

2− 2x−9 x2−5x

!

: x−6

x2−7x : x−7

2 = [R: ]

(f) x−8 2x−14 : 1

4 − x−6 x2−7x

!

= [R: ]

6. Reši enaˇcbe:

(a) 3x−1

2x−6 − 6x−5 x−3 = 9

2 [R:2]

(b) 5

8−2x − 1

3x−12 +3 +x x−4 = 1

6 [R:−1]

(c) 5x−1

3x−2 − 5x+ 7

3x+ 2 = 2(13−3x)

9x2−4 [R:7]

(d) 4x−7

2x−5 − 4x+ 1

2x+ 5 = 3(5x+ 8)

4x2−25 [R:6]

(e) 2x−5

x+ 2 − x−2

x−3 = x2−3

x2−x−6 [R:2]

(f) x−1

x+ 2 − 3x

5−x− 4x2−3x+ 6

x2−3x−10 = 0 [R: 13]

Reference

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